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X^2+9X^2=160
We move all terms to the left:
X^2+9X^2-(160)=0
We add all the numbers together, and all the variables
10X^2-160=0
a = 10; b = 0; c = -160;
Δ = b2-4ac
Δ = 02-4·10·(-160)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*10}=\frac{-80}{20} =-4 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*10}=\frac{80}{20} =4 $
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